$-16\cdot8$
$\frac{6x^2+42x+38}{x+6}$
$\left(a^2+4\right)\left(a-2\right)\left(a+2\right)$
$10x-10-6\left(x+2\right)$
$\frac{6}{x-2}=\frac{10}{x}$
$x^6+4x^4$
$\left(x+5\right)\left(x-2\right)\left(x-5\right)$
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