$x'\:+\:5x^2\:=\:25$
$7x+2bd+3bd-7x$
$2n\left(n^3+3n^2\right)=4n$
$\frac{\left(4x^2-2x+7\right)}{\left(x-1\right)}$
$36m^4-4n^2$
$\int\frac{4}{x^2+16}dx$
$\frac{1-4\tan^2\left(x\right)}{1-2\tan\left(x\right)}=1+2\tan\left(x\right)$
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