$\int\:\frac{x+4}{x^2+5x-6}dx$
$\left(4x^3+20x^2-8x-96\right)\left(x+3\right)$
$\frac{\infty^{-1}}{-1}$
$\left(5y+6\right)\left(5y-6\right)$
$\left(-2\right).\left(-3\right).\left(-4\right).\left(-5\right)$
$2+\frac{1}{x^2}$
$\frac{dy}{dx}=7$
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