$4\left(2u+4\right)-12u$
$\sqrt{4+4x^2}$
$\left(3x^2y^4z^5\right)\left(-8x^2y^4\right)\left(-4x^2y^4z^5\right)$
$12\cdot\left(-3\right)+40$
$\frac{dy}{dx}\left(\frac{x^2}{7}+\frac{y^2}{4}=1\right)$
$\sqrt{36\:+\:\:\sqrt{49}}$
$\left(\frac{3x^{-4}}{r^4}\right)^2$
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