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# Solve the product $\left(x^2-3\right)\left(-3-x^2\right)$

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##  Final answer to the problem

$-x^{4}+9$
Got another answer? Verify it here!

##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Product of Binomials with Common Term
• FOIL Method
• Find the integral
• Find the derivative
• Factor
• Integrate by partial fractions
• Integrate by substitution
• Integrate by parts
• Integrate using tabular integration
Can't find a method? Tell us so we can add it.
1

Multiply the single term $-3-x^2$ by each term of the polynomial $\left(x^2-3\right)$

$x^2\left(-3-x^2\right)-3\left(-3-x^2\right)$

Learn how to solve special products problems step by step online.

$x^2\left(-3-x^2\right)-3\left(-3-x^2\right)$

Learn how to solve special products problems step by step online. Solve the product (x^2-3)(-3-x^2). Multiply the single term -3-x^2 by each term of the polynomial \left(x^2-3\right). Multiply the single term x^2 by each term of the polynomial \left(-3-x^2\right). When multiplying exponents with same base we can add the exponents. Multiply the single term -3 by each term of the polynomial \left(-3-x^2\right).

##  Final answer to the problem

$-x^{4}+9$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.