$\frac{\left(ax^3-axy+x^3y-xy^3\right)}{x^2-xy}$
$3x^2+6y+12xy$
$\lim_{x\to\infty}\left(\frac{-2x+6}{x^2+4}\right)$
$x^2+6x+14$
$16x^2+y^2-8xy$
$43mx+3-4x-2y-3x-5$
$4\left(2\right)\left(2\right)\frac{3}{2}$
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