$\left(m^2n^3+8qp\right)^2$
$\frac{1}{x}+\frac{1}{x+3}=\frac{3}{10}$
$-x^2-x-2$
$1-2z+4z^2$
$\left(-11\right)\left(+7\right)\left(+8\right)$
$3^0-5^1+5^0$
$\lim_{x\to\infty\:}\left(\frac{11-81^{\frac{489}{x}}}{4}\right)^x$
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