$\frac{1-3x^5}{x^3+3}$
$2x\cdot x^6$
$10-10\left[-6+5\left(-4+7-3\right)\right]$
$a+1^2$
$\int\frac{1}{\left(4x^2+1\right)\left(2x+1\right)}dx$
$-2\left(y+5\right)+3y$
$\lim_{x\to-\infty}\left(\sqrt{x^2+3}-x\right)\arctan\left(x\right)$
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