$\left(7x^4y^7z^2\right)^6$
$\frac{\left(2y^2-3y+5\right)}{\left(y^2-5y+2\right)}$
$162\cdot3$
$\frac{3}{4}ab-ab^2\frac{1}{4}ab$
$\left(-x^4y^3\right)^0\cdot\left(2x^3\right)^2$
$2 x ^ { 3 } - 6 x + 4$
$-74.3751-372.5860-361.4488-113.4692-95.6550$
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