$0.02-0.2-1$
$\int_{1}^{+\infty}\frac{x}{\sqrt{x^{2}+2}}dx$
$\frac{dy}{dx}=\frac{3x-4}{\left(5x+6\right)^4}$
$\left(4x\:-7y\:-5z\right)^2$
$\frac{4x^3-14x^2-10x+4}{2x-4}$
$3\left(x-y\right)+4\left(x+2y\right)$
$\frac{dy}{dx}=\frac{2x}{y^2},\:y\left(1\right)=1$
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