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$\left(x^2+2xh+h^2-4x-4h\right)-\left(x^2-4x\right)$

Final answer to the exercise

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Other solved exercises

$440\cdot60$

$9\:cos^2x\:=\:12\:cos\:x\:-\:4$

$\left(9^2\right)^3+\left(\left(-4\right)^2\right)^3$

$+2500+3000-2550$

$\frac{a^3+5a^2+a-1}{a+5}$

$6^{x+3}=-1$

$10^2-2\cdot10\cdot6+6^2$
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