$6x^2\cdot\left(2x^2\right)^5$
$\pi\int_2^3\left(\sqrt{\sec\left(2x\right)}\tan\left(2x\right)\right)dx$
$x^2-5x+6\ge x+5$
$\lim_{x\to2\pi}\left(\cot\left(x\right)\right)$
$1\cdot1\cdot\left(x^2\right)$
$e^x\cdot e$
$\left(-2\right)^3\cdot\left(-2\right)^4$
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