$x^2-4x>-3$
$\left(x+m+y^2\right)\left(x+m-y^2\right)$
$\frac{1}{6}x^{10}+\frac{7}{2}x^5+49$
$\int\left(\frac{x}{\left(4t^2+9\right)}\right)dx$
$0.2x\:-\:1\:=\:-1$
$42 = - 7 ( z - 3 )$
$12x^2+5x-2=0$
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