$\left(10\right)-\left(-8\right)$
$\int_0^1\left(\frac{3x}{\left(x+2\right)\left(x-5\right)}\right)dx$
$\lim\:_{x\to\:\:24}\frac{7x^2-141x+152}{3x^2-\left(s+57\right)x+19s}$
$6x+6+x=41$
$\frac{2-2x}{x-3}\ge2$
$-3+\frac{6}{3}$
$x^2\:-\:6x\:=\:16$
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