$2+3x+3$
$\lim_{x\to\infty}\left(\frac{3e^{x-2}}{x^2+6x}\right)$
$\int_0^{\infty}\left(\frac{8\arctan\left(x\right)}{1+x^2}\right)dx$
$\int\frac{14y^6}{\sqrt{9-y^{14}}}dx$
$2.20\cdot15$
$\frac{x^4-x^3+4x+1}{x^2+3}$
$x\ln\:\left(6\right)=x\ln\:\left(3\right)$
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