$\frac{\left(x+5\right)}{\left(x+1\right)\left(x-3\right)}$
$\left(+2\right)\cdot\left(+4\right)+\left(+2\right)\cdot\left(+8\right)$
$1-16a^4b^6c^2$
$\lim_{x\to0}\left(\tan\left(2x\right)\right)$
$\frac{125x^3y^6+8}{5xy^2+2}$
$\int\:\frac{\left(e^x\right)}{\left(1\:+\:e^x\right)}dx$
$\int_0^1x^{-3}dx$
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