$3x\left(2x-1\right)^2-2\left(x-3\right)\left(x+3\right)$
$\frac{6p^6p^2}{2p^2p^2}$
$\left(a-1\right)x+\left(b-2\right)x=\left(x-3\right)a+\left(x-3\right)b$
$7+5+9+12+8+3$
$-8-4352$
$x^3-8x^2+16x-5$
$\left(x^3-\frac{3}{5}\right)\left(x^3+\frac{3}{5}\right)$
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