$\int_0^4\left(3\sqrt{16-x^2}\right)dx$
$418+649-891+151$
$2\int e^{x^2}xdx$
$\lim_{x\to3}\left(2x^2+5x+3\right)$
$-5\cdot10$
$-12\cos\left(6x\right)\sin\left(6x\right)+16\sin\left(8x\right)\cos\left(8x\right)$
$\int_1^3\left(\sqrt{1\:+\frac{1}{2\sqrt{x}}}\right)dx$
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