$4\cos\left(2x\right)=10$
$\frac{25}{4}+\frac{16x^2}{36}-\frac{10}{3}x$
$\left(-12\right).\:x=-48$
$\frac{\cos\left(x\right)+\sin\left(x\right)}{\cos\left(x\right)-\sin\left(x\right)}=\sec2\left(x\right)+\tan2\left(x\right)$
$4z^2-16=36$
$144\:^2$
$144m^6-121x^8y^4$
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