$\int\:\frac{4x}{\left(2x^2+3\right)^3}dx$
$x_{-3y\:per\:a\:x=2,y=_{-1}}$
$\int_0^c\left(\left(x-c\right)^2\right)dx$
$\frac{1}{-\cos^2\left(x\right)}=2$
$\frac{5-21}{-3+4i}$
$4a^2+12a+6$
$\frac{-7}{2}.\frac{2}{1}$
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