$x\left(3-2b\right)-1=x\left(2-3b\right)-b$
$-18\left(12+13\right)$
$-25-\left(-9\right)$
$2\cdot36$
$\left(10x^{\frac{1}{7}}\right)^3-\left(8z^{15}y^{\frac{2}{7}}\right)^3$
$2r+3s-5r$
$3xy\left(4xy^2+5y-6x^2\right)$
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