$\lim_{x\to\infty}\left(\frac{x^2-1}{e^{x^2}}\right)$
$2x+9>11$
$\left(m-2\right)\left(m-12\right)$
$\lim_{x\to9}\left(\frac{x^2-16}{\sqrt{x}-2}\right)$
$sec^2\:x=tan\:x+1$
$0.2\cdot3829$
$583\cdot49$
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