$\int\left(2\cdot\cos\left(2x+3\right)\right)dx$
$\int\frac{3x^3-9x^2+7}{x^2-x}dx$
$e^{x+y}=1$
$0=-500q+60q^2$
$.5x+6=x-4$
$\frac{\left(2+x\right)^3-\left(2+x\right)-6}{x}$
$x y ^ { \prime } = - x$
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