$\frac{d^2x}{dt^2}-\:9.8\:=0$
$p^3+q^3$
$\left(x+\frac{1}{2}\right)\left(x-\frac{1}{2}\right)$
$7x+2pq+3pq-7x+pq+2x$
$\frac{d}{dx}\sqrt{\frac{x-1}{x^4+\:4\:}}$
$5x^2\left(9a-6b\right)-10x\left(9a-6b\right)$
$b-6=0$
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