$\int\ln\left(\left(\frac{2x^2-3}{4}\right)\right)dx$
$\frac{x+19}{3}=9$
$\frac{d}{dx}-3xy=15x^2$
$\left(\left(4x\right)^5-\left(3y\right)^4\right)^2$
$59\cdot19$
$\frac{x^6-x^6}{x+x}$
$\left|3\right|+-\left|6\right|$
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