$\frac{d}{dx}\left(\frac{-1}{8}\ln\left(x+2\right)+\frac{1}{8}\ln\left(x+3\right)-\frac{1}{8x+24}\right)$
$\frac{8}{x^2-x}+\frac{1}{x}=\frac{8}{x-1}$
$\frac{2x^3-3x^2-5x+4}{x+2}$
$20x^2+100x+125$
$3x^2-7x-2$
$\left(5-x\right)^4$
$3\cdot y-8\cdot z+9^2$
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