$f\left(x\right)=\left(x^5+1\right)^2$
$-15+\left(-9+10\right)^3-3\left(-8\right)^0\left(-2\right)^2$
$\left(\sqrt{\frac{a^3}{b^5}}\right)^2$
$36x^2=25$
$x^2-25<0$
$x^{16}-19^2$
$\theta\csc ydx+\sec^{2}xdy=0$
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