$\lim_{x\to\infty}\left(3xe^{\frac{1}{x}}-3x\right)$
$\int\left(\frac{1}{2}x+1\right)\frac{1}{2}x\:dx$
$-\sqrt{24}$
$\left(7a^2-b^2\right)\left(7a^2+4b^2\right)$
$\frac{4}{m+8}-\frac{2}{m+3}=\frac{14}{m^2+11m+24}$
$11\sqrt{99}$
$4r+4y-8$
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