$3\left(-2\right)^5$
$196x^2y^4-225z^12$
$\left(6^4.2\right)^3$
$\frac{2^x+3^x}{6^x}$
$\left(3+2i\right)^2+3i^{15}\left(3-2i^2\right)$
$\left(3-25\right)\cdot\left(-1\right)$
$\left(y+1\right)\left(y+5\right)$
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