$\left(24m-9a^8\right)\left(6b^4-10n^5+12\right)$

$\left(x+1\right)\left(x+2\right)+\left(x-1\right)\left(x-2\right)$

$\int\frac{\left(2x^2+3x+2\right)}{\left(x+2\right)\left(x^2+2x+3\right)}dx$

$320+-210+-165+412+382$

$\left(4^8\right)^3$

$-28-\left(-21\right)$

$5\sin\left(x\right)\tan\left(x\right)=4\tan\left(x\right)$