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# Solve the inequality $\left(x+3\right)\left(x-2\right)-2\geq \left(x-2\right)\left(x+2\right)$

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##  Final Answer

$x\geq 4$
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##  Step-by-step Solution 

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The product of two binomials of the form $(x+a)(x+b)$ is equal to the product of the first terms of the binomials, plus the algebraic sum of the second terms by the common term of the binomials, plus the product of the second terms of the binomials. In other words: $(x+a)(x+b)=x^2+(a+b)x+ab$

$x^2+\left(3-2\right)x+3\cdot -2-2\geq \left(x-2\right)\left(x+2\right)$

Learn how to solve one-variable linear inequalities problems step by step online.

$x^2+\left(3-2\right)x+3\cdot -2-2\geq \left(x-2\right)\left(x+2\right)$

Learn how to solve one-variable linear inequalities problems step by step online. Solve the inequality (x+3)(x-2)-2>=(x-2)(x+2). The product of two binomials of the form (x+a)(x+b) is equal to the product of the first terms of the binomials, plus the algebraic sum of the second terms by the common term of the binomials, plus the product of the second terms of the binomials. In other words: (x+a)(x+b)=x^2+(a+b)x+ab. Subtract the values 3 and -2. Multiply 3 times -2. Subtract the values -6 and -2.

##  Final Answer

$x\geq 4$

SnapXam A2

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

### Main Topic: One-variable linear inequalities

Algebraic inequalities that have just one variable.

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