$\int_{\frac{\pi\:}{4}}^{\frac{\pi\:}{2}}\frac{tan\left(x+1\right)}{cos\left(x+1\right)}dx$
$3\:\le8+x$
$\left(\frac{x^2}{y}\right)^4$
$\frac{6x}{\left(x^2+3\right)^2}$
$\lim_{x\to-3}\left(\frac{x^2-9}{x+1}\right)$
$4yx^4.3x^3y^4$
$5xy\frac{dy}{dx}+y=0$
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