$\left(3x^3-x\right)\left(\sqrt[3]{x}+\frac{2}{x^2}\right)$
$x^3+3x^2-5-6$
$236\sqrt{12}$
$4-\frac{12}{6}$
$2x>\frac{3}{2}x-1$
$b^3c^2,b=-4,c=5$
$\left(\frac{2}{3}x^{\frac{-1}{2}}y^{\frac{3}{4}}-\frac{3}{4}x^{\frac{-3}{2}}y^{\frac{-1}{4}}\right)^2$
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