$16x^3-21x^2+6x$
$\frac{9x^2+6x+1}{3x+1}$
$\frac{\left(1-\sin\left(x\right)^2\right)\left(1+\sin\left(x\right)^2\right)}{\cos\left(x\right)^2}=1$
$-6754-2345$
$\lim_{x\to0}\left(\left(9x\right)^{\left(sin\left(4x\right)\right)}\right)$
$\left|\left(5^2\right)^3\right|^4$
$4096x^12-y^6$
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