$\left(3x+1\right)\left(2x-4\right)-6x^2+10x-4$
$x^2-22x-75$
$tan\left(2\theta\:\right)=\frac{2}{\left(cot\left(\theta\:\right)-tan\left(\theta\:\right)\right)}$
$m^2+4m-6$
$3x<9x+4$
$65,3\:x\:129,9$
$9^3+2$
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