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Find the roots of $\left(x+1\right)\left(x-2\right)=0$

Step-by-step Solution

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sinh
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asinh
acosh
atanh
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Final Answer

$x=-1,\:x=2$
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Step-by-step Solution

Specify the solving method

1

Break the equation in $2$ factors and set each equal to zero, to obtain

$x+1=0,\:x-2=0$
2

Solve the equation ($1$)

$x+1=0$
3

We need to isolate the dependent variable $x$, we can do that by simultaneously subtracting $1$ from both sides of the equation

$x+1-1=0-1$
4

Canceling terms on both sides

$x=-1$
5

Solve the equation ($2$)

$x-2=0$
6

We need to isolate the dependent variable $x$, we can do that by simultaneously subtracting $-2$ from both sides of the equation

$x-2+2=0+2$
7

Canceling terms on both sides

$x=2$
8

Combining all solutions, the $2$ solutions of the equation are

$x=-1,\:x=2$

Final Answer

$x=-1,\:x=2$

Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve for xSolve by factoringSolve by completing the squareSolve by quadratic formula (general formula)Find break even pointsFind the discriminant

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Function Plot

Plotting: $\left(x+1\right)\left(x-2\right)$

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Answer Assistant

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Got a different answer? Verify it!

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

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