$-3+5x\:;\:x=-2\:$
$x^3+5x^2-8x-48$
$\lim_{x\to2}\left(\frac{x^3-3x+2}{x^2-x-6}\right)$
$\frac{dy}{dx}=\frac{xy}{x^2-3}$
$\frac{4a^{-2}}{\left(4a\right)^2}$
$9^2-16$
$\left(\frac{1+y^2}{y^2}\right)\frac{dy}{dx}=\frac{1}{1+x^2}$
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