$\int\left(16x\:cos\left(8x^2-3\right)\right)dx$
$\frac{d^4}{dx^4}\:x^3$
$\frac{-x^3+4x^2-8}{x-2}$
$\frac{216-x^3y^6}{6+x^2}$
$y'=7x^5$
$-9+3x^2-y^2-\left(6+6x^2-3y^2\right)-4$
$\int e^x\cdot\sin\left(7x\right)dx$
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