$18x^3+12x^2-6x$
$\left(1+x^2y\right)dy=\left(-xy^2\right)dx$
$7b:b+4$
$\int\sinh\left(x\right)\left(\cosh\left(x\right)^2\right)dx$
$6x^4y-12x^3y-18x^2y$
$\int\frac{6}{e^{-3x}}dx$
$\int\frac{\left(x^2+6x+11\right)}{\left(x+2\right)}dx$
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