$-\:12\:ab\:+\:7\:ab$
$\left(\frac{5}{6}b^2+\frac{1}{5}\right)^2$
$-12+32+-21+-17+59$
$0.122+0.992x-4.96+\frac{-0.122x^2+1.22x-3.05}{2}+\frac{-0.992x^3+14.88x^2-74.4x+124}{6}$
$\left(5x^3y\right)\left(2x^3y\right)$
$\left(x+y+1\right)^3-\left(x+y\right)^3-x^3+y^3$
$x+1=4x+1$
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