$-4\:-1+\:8\:-13\:\:-1\:$
$\int\:cot^6\left(5x+3\right)\:dx$
$3x-6>2x-12$
$\left(7-3\right)^3-3^2+\left(6-1\right)^2$
$x^2-12x=-36$
$\frac{x^2+6x+2}{x^2-3}$
$16\:x\:\frac{3}{4}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!