$x^2+4x+5$
$\left(\left(2a-1\right)\left(2a^2+a\right)-4a\right)\left(2a-1\right)$
$-3a^2b+8ab^2-b^3$
$\left(4x+3\right)\left(2x+7\right)$
$\left(2s+\frac{1}{3}\right)\left(2s-\frac{1}{3}\right)$
$5x^4y-xy;\:x=-2;\:y=-3$
$-12^1$
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