$\lim_{x\to-2}\left(\frac{y^2-4}{y^2+4y+4}\right)$
$\lim_{x\to1}\left(-3x^3-7\right)$
$16^2+4^3\cdot2$
$\frac{64x^6-81^4}{9y+8x}$
$\frac{dx}{dy}=1.5y^2-2x$
$\int\left(3x-1\right)^3dx$
$2x^3+6$
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