$4\csc x+9=0$
$y^2-5y+8=3y-8$
$y'=e^{4x}-5senx\:$
$\frac{dy}{dx}=\frac{1}{2x+y}$
$sin\left(\theta\right)\sec3\left(\theta\right)$
$4y\cdot y'+x=0$
$-4\left(-3z-2\right)-9$
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