$\frac{d}{dx}6^x$
$y2\:-\:9y\:+\:20$
$y-3xy=3y^2+y$
$\left(6ac^3\right)\cdot\left(-2x^2c^3\right)\cdot\left(-3ac\right)\cdot\left(-4a^3c^2\right)$
$4x-3-5x-9$
$3x^3y^2\left(4x^3-5xy\right)-4y^2\left(x^6-3x^4y\right)$
$\frac{d}{dx}\frac{\sin x-1}{\cos x}$
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