$\int\frac{x}{\sqrt[2]{1-x^2}}\cdot ln\left(\frac{x-1}{x+1}\right)dx$

$\frac{dy}{dx}=\frac{\:e^{2x+y}}{\:e^{x-y}}$

$\frac{dy}{dx}=\tan\left(4\cdot x\right)$

$3x^2\:entre\:3$

$\left(4t^3+3\right)^3$

$\frac{1}{\sqrt{1-\frac{2b}{a}\sin\left(b\right)\sin\left(c\right)}}$

$\int4^{3x}dx$