$x^5-x^3y^2$
$-x+2<3$
$3.851+38$
$-\left(4+\right)\left(3^2-6\right)$
$\lim_{x\to\infty}\left(\frac{2x+1}{3x+4}\right)^x$
$\left(\frac{\frac{3}{2}x^3y}{4x^4y}\right)^2$
$\frac{dx}{dt}=8-3y$
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