$\frac{1}{2}\left(4x+8\right)=2x+8$
$\cos^2\left(x\right)-sin^2\left(x\right)-\sqrt{3}cos\left(x\right)=-1$
$x^2-15x-10$
$-\frac{44}{4}$
$\:0\::\:-\:45$
$\frac{x+2}{x^2+4x+4}:\:\frac{x^2+5x+6}{x+3}$
$-ih\left[-aksin\left(kx\right)+iakcos\left(kx\right)\right]$
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