$y^5+4y^3=0$
$\sqrt{5x}^2\cdot\sqrt{15x^3}$
$+4\:+\:-10\:+\:-17\:+\:-6$
$\left(5a^2b\:-\:1\right)\left(5a^2+\:1\right)\:$
$\lim_{x\to0}\left(\frac{5x\cosh\left(\sinh\left(3x\right)\right)}{\tan\left(2x\right)}\right)$
$\frac{\cot^2a-\cos^2a}{\csc^2a-1}=\cos^2a$
$\lim_{x\to2}\left(\frac{e^{2x-1}-e}{x^2-4}\right)$
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