$\int_{\sqrt{36-x^2}}^xdx$
$\frac{x^4-1}{x^2+2x}$
$\int\frac{1+3x}{x^3}dx$
$\frac{1}{\sqrt{x}}=\frac{d^2x}{dz^2}$
$\int\frac{5+3x+6x^2-2x^3}{x^2}dx$
$3y^2+5y-2$
$\left(-5682\right)\cdot\left(-69\right)$
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